1/2x-x+3/2x=+4

Solution for 1/2x-x+3/2x=+4 equation:

1/2x-x+3/2x=+4

We move all terms to the left:

1/2x-x+3/2x-(+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x-x+3/2x-4=0

We add all the numbers together, and all the variables

-1x+1/2x+3/2x-4=0

We multiply all the terms by the denominator


-1x*2x-4*2x+1+3=0

We add all the numbers together, and all the variables

-1x*2x-4*2x+4=0

Wy multiply elements

-2x^2-8x+4=0

a = -2; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·(-2)·4
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{6}}{2*-2}=\frac{8-4\sqrt{6}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{6}}{2*-2}=\frac{8+4\sqrt{6}}{-4}
$