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1/2x-x=6+3/2x
We move all terms to the left:
1/2x-x-(6+3/2x)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/2x-x-(3/2x+6)=0
We add all the numbers together, and all the variables
-1x+1/2x-(3/2x+6)=0
We get rid of parentheses
-1x+1/2x-3/2x-6=0
We multiply all the terms by the denominator
-1x*2x-6*2x+1-3=0
We add all the numbers together, and all the variables
-1x*2x-6*2x-2=0
Wy multiply elements
-2x^2-12x-2=0
a = -2; b = -12; c = -2;
Δ = b2-4ac
Δ = -122-4·(-2)·(-2)
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-8\sqrt{2}}{2*-2}=\frac{12-8\sqrt{2}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+8\sqrt{2}}{2*-2}=\frac{12+8\sqrt{2}}{-4} $
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