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1/2x=-3x+5
We move all terms to the left:
1/2x-(-3x+5)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x+3x-5=0
We multiply all the terms by the denominator
3x*2x-5*2x+1=0
Wy multiply elements
6x^2-10x+1=0
a = 6; b = -10; c = +1;
Δ = b2-4ac
Δ = -102-4·6·1
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{19}}{2*6}=\frac{10-2\sqrt{19}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{19}}{2*6}=\frac{10+2\sqrt{19}}{12} $
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