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1/2x=50-x
We move all terms to the left:
1/2x-(50-x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-(-1x+50)=0
We get rid of parentheses
1/2x+1x-50=0
We multiply all the terms by the denominator
1x*2x-50*2x+1=0
Wy multiply elements
2x^2-100x+1=0
a = 2; b = -100; c = +1;
Δ = b2-4ac
Δ = -1002-4·2·1
Δ = 9992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9992}=\sqrt{4*2498}=\sqrt{4}*\sqrt{2498}=2\sqrt{2498}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-2\sqrt{2498}}{2*2}=\frac{100-2\sqrt{2498}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+2\sqrt{2498}}{2*2}=\frac{100+2\sqrt{2498}}{4} $
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