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1/2x=x-16
We move all terms to the left:
1/2x-(x-16)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-x+16=0
We multiply all the terms by the denominator
-x*2x+16*2x+1=0
Wy multiply elements
-2x^2+32x+1=0
a = -2; b = 32; c = +1;
Δ = b2-4ac
Δ = 322-4·(-2)·1
Δ = 1032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1032}=\sqrt{4*258}=\sqrt{4}*\sqrt{258}=2\sqrt{258}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-2\sqrt{258}}{2*-2}=\frac{-32-2\sqrt{258}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+2\sqrt{258}}{2*-2}=\frac{-32+2\sqrt{258}}{-4} $
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