1/2y(-9)+3y=19

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Solution for 1/2y(-9)+3y=19 equation: 



1/2y(-9)+3y=19

We move all terms to the left:

1/2y(-9)+3y-(19)=0



Domain of the equation: 2y(-9)!=0

y∈R



We add all the numbers together, and all the variables

3y+1/2y(-9)-19=0

We multiply all the terms by the denominator


3y*2y(-9)-19*2y(-9)+1=0

Wy multiply elements

6y^2(--38y(-+1=0

We use the square of the difference formula

6y^2(+38y(-1=0

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