1/2y+1/(y+1)=1/3

Solution for 1/2y+1/(y+1)=1/3 equation:

1/2y+1/(y+1)=1/3

We move all terms to the left:

1/2y+1/(y+1)-(1/3)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: (y+1)!=0

We move all terms containing y to the left, all other terms to the right

y!=-1

y∈R


We add all the numbers together, and all the variables

1/2y+1/(y+1)-(+1/3)=0

We get rid of parentheses

1/2y+1/(y+1)-1/3=0

We calculate fractions


(-2y^2*()/(6y^2+6y)+(3y+3)/(6y^2+6y)+18y/(6y^2+6y)=0


We calculate terms in parentheses: +(-2y^2*()/(6y^2+6y)+(3y+3)/(6y^2+6y)+18y/(6y^2+6y), so:

-2y^2*()/(6y^2+6y)+(3y+3)/(6y^2+6y)+18y/(6y^2+6y

We calculate fractions

We do not support eypression: y^3