1/2y+1/2(y+2)=5+3(y-3)

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Solution for 1/2y+1/2(y+2)=5+3(y-3) equation: 



1/2y+1/2(y+2)=5+3(y-3)

We move all terms to the left:

1/2y+1/2(y+2)-(5+3(y-3))=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R





Domain of the equation: 2(y+2)!=0

y∈R



We calculate fractions


-(5+3(y-3))+(2yy/(4y^2y+2y/(4y^2y=0



We calculate terms in parentheses: -(5+3(y-3)), so:

5+3(y-3)

determiningTheFunctionDomain
3(y-3)+5

We multiply parentheses

3y-9+5

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)



We can not solve this equation

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