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1/2y+1/4y=-6
We move all terms to the left:
1/2y+1/4y-(-6)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 4y!=0We add all the numbers together, and all the variables
y!=0/4
y!=0
y∈R
1/2y+1/4y+6=0
We calculate fractions
4y/8y^2+2y/8y^2+6=0
We multiply all the terms by the denominator
4y+2y+6*8y^2=0
We add all the numbers together, and all the variables
6y+6*8y^2=0
Wy multiply elements
48y^2+6y=0
a = 48; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·48·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*48}=\frac{-12}{96} =-1/8 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*48}=\frac{0}{96} =0 $
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