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1/2y+11+1/6y=9
We move all terms to the left:
1/2y+11+1/6y-(9)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 6y!=0We add all the numbers together, and all the variables
y!=0/6
y!=0
y∈R
1/2y+1/6y+2=0
We calculate fractions
6y/12y^2+2y/12y^2+2=0
We multiply all the terms by the denominator
6y+2y+2*12y^2=0
We add all the numbers together, and all the variables
8y+2*12y^2=0
Wy multiply elements
24y^2+8y=0
a = 24; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·24·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*24}=\frac{-16}{48} =-1/3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*24}=\frac{0}{48} =0 $
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