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1/2y+11=2y
We move all terms to the left:
1/2y+11-(2y)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
-2y+1/2y+11=0
We multiply all the terms by the denominator
-2y*2y+11*2y+1=0
Wy multiply elements
-4y^2+22y+1=0
a = -4; b = 22; c = +1;
Δ = b2-4ac
Δ = 222-4·(-4)·1
Δ = 500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{500}=\sqrt{100*5}=\sqrt{100}*\sqrt{5}=10\sqrt{5}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10\sqrt{5}}{2*-4}=\frac{-22-10\sqrt{5}}{-8} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10\sqrt{5}}{2*-4}=\frac{-22+10\sqrt{5}}{-8} $
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