1/2y+2-y=1

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Solution for 1/2y+2-y=1 equation:



1/2y+2-y=1
We move all terms to the left:
1/2y+2-y-(1)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
We add all the numbers together, and all the variables
-1y+1/2y+1=0
We multiply all the terms by the denominator
-1y*2y+1*2y+1=0
Wy multiply elements
-2y^2+2y+1=0
a = -2; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-2)·1
Δ = 12
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12}=\sqrt{4*3}=\sqrt{4}*\sqrt{3}=2\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{3}}{2*-2}=\frac{-2-2\sqrt{3}}{-4} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{3}}{2*-2}=\frac{-2+2\sqrt{3}}{-4} $

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