1/2y+3/4y=-20

Solution for 1/2y+3/4y=-20 equation:

1/2y+3/4y=-20

We move all terms to the left:

1/2y+3/4y-(-20)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We add all the numbers together, and all the variables

1/2y+3/4y+20=0

We calculate fractions


4y/8y^2+6y/8y^2+20=0

We multiply all the terms by the denominator


4y+6y+20*8y^2=0

We add all the numbers together, and all the variables

10y+20*8y^2=0

Wy multiply elements

160y^2+10y=0

a = 160; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·160·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*160}=\frac{-20}{320}
=-1/16
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*160}=\frac{0}{320}
=0
$