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1/2y+6+3/2y=2y-6y-30
We move all terms to the left:
1/2y+6+3/2y-(2y-6y-30)=0
Domain of the equation: 2y!=0We add all the numbers together, and all the variables
y!=0/2
y!=0
y∈R
1/2y+3/2y-(-4y-30)+6=0
We get rid of parentheses
1/2y+3/2y+4y+30+6=0
We multiply all the terms by the denominator
4y*2y+30*2y+6*2y+1+3=0
We add all the numbers together, and all the variables
4y*2y+30*2y+6*2y+4=0
Wy multiply elements
8y^2+60y+12y+4=0
We add all the numbers together, and all the variables
8y^2+72y+4=0
a = 8; b = 72; c = +4;
Δ = b2-4ac
Δ = 722-4·8·4
Δ = 5056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5056}=\sqrt{64*79}=\sqrt{64}*\sqrt{79}=8\sqrt{79}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-8\sqrt{79}}{2*8}=\frac{-72-8\sqrt{79}}{16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+8\sqrt{79}}{2*8}=\frac{-72+8\sqrt{79}}{16} $
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