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1/2y-1/3y=6
We move all terms to the left:
1/2y-1/3y-(6)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 3y!=0We calculate fractions
y!=0/3
y!=0
y∈R
3y/6y^2+(-2y)/6y^2-6=0
We multiply all the terms by the denominator
3y+(-2y)-6*6y^2=0
Wy multiply elements
-36y^2+3y+(-2y)=0
We get rid of parentheses
-36y^2+3y-2y=0
We add all the numbers together, and all the variables
-36y^2+y=0
a = -36; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-36)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-36}=\frac{-2}{-72} =1/36 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-36}=\frac{0}{-72} =0 $
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