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1/2y-5/6y+1/3=1/2
We move all terms to the left:
1/2y-5/6y+1/3-(1/2)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 6y!=0We add all the numbers together, and all the variables
y!=0/6
y!=0
y∈R
1/2y-5/6y+1/3-(+1/2)=0
We get rid of parentheses
1/2y-5/6y+1/3-1/2=0
We calculate fractions
144y^2/216y^2+54y/216y^2+(-180y)/216y^2+(-54y)/216y^2=0
We multiply all the terms by the denominator
144y^2+54y+(-180y)+(-54y)=0
We get rid of parentheses
144y^2+54y-180y-54y=0
We add all the numbers together, and all the variables
144y^2-180y=0
a = 144; b = -180; c = 0;
Δ = b2-4ac
Δ = -1802-4·144·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-180}{2*144}=\frac{0}{288} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+180}{2*144}=\frac{360}{288} =1+1/4 $
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