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1/2y-6=1/7y
We move all terms to the left:
1/2y-6-(1/7y)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 7y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/2y-(+1/7y)-6=0
We get rid of parentheses
1/2y-1/7y-6=0
We calculate fractions
7y/14y^2+(-2y)/14y^2-6=0
We multiply all the terms by the denominator
7y+(-2y)-6*14y^2=0
Wy multiply elements
-84y^2+7y+(-2y)=0
We get rid of parentheses
-84y^2+7y-2y=0
We add all the numbers together, and all the variables
-84y^2+5y=0
a = -84; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-84)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-84}=\frac{-10}{-168} =5/84 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-84}=\frac{0}{-168} =0 $
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