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1/2y-9=1/10y
We move all terms to the left:
1/2y-9-(1/10y)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 10y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/2y-(+1/10y)-9=0
We get rid of parentheses
1/2y-1/10y-9=0
We calculate fractions
10y/20y^2+(-2y)/20y^2-9=0
We multiply all the terms by the denominator
10y+(-2y)-9*20y^2=0
Wy multiply elements
-180y^2+10y+(-2y)=0
We get rid of parentheses
-180y^2+10y-2y=0
We add all the numbers together, and all the variables
-180y^2+8y=0
a = -180; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-180)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-180}=\frac{-16}{-360} =2/45 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-180}=\frac{0}{-360} =0 $
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