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1/2y=y+10
We move all terms to the left:
1/2y-(y+10)=0
Domain of the equation: 2y!=0We get rid of parentheses
y!=0/2
y!=0
y∈R
1/2y-y-10=0
We multiply all the terms by the denominator
-y*2y-10*2y+1=0
Wy multiply elements
-2y^2-20y+1=0
a = -2; b = -20; c = +1;
Δ = b2-4ac
Δ = -202-4·(-2)·1
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{102}}{2*-2}=\frac{20-2\sqrt{102}}{-4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{102}}{2*-2}=\frac{20+2\sqrt{102}}{-4} $
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