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1/2y=y-2
We move all terms to the left:
1/2y-(y-2)=0
Domain of the equation: 2y!=0We get rid of parentheses
y!=0/2
y!=0
y∈R
1/2y-y+2=0
We multiply all the terms by the denominator
-y*2y+2*2y+1=0
Wy multiply elements
-2y^2+4y+1=0
a = -2; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-2)·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{6}}{2*-2}=\frac{-4-2\sqrt{6}}{-4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{6}}{2*-2}=\frac{-4+2\sqrt{6}}{-4} $
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