1/2z+1/3z=1/2+7

Solution for 1/2z+1/3z=1/2+7 equation:

1/2z+1/3z=1/2+7

We move all terms to the left:

1/2z+1/3z-(1/2+7)=0


Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R


We get rid of parentheses

1/2z+1/3z-7-1/2=0

We calculate fractions


3z/24z^2+8z/24z^2+(-3z)/24z^2-7=0

We multiply all the terms by the denominator


3z+8z+(-3z)-7*24z^2=0

We add all the numbers together, and all the variables

11z+(-3z)-7*24z^2=0

Wy multiply elements

-168z^2+11z+(-3z)=0

We get rid of parentheses

-168z^2+11z-3z=0

We add all the numbers together, and all the variables

-168z^2+8z=0

a = -168; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·(-168)·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*-168}=\frac{-16}{-336}
=1/21
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*-168}=\frac{0}{-336}
=0
$