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1/2z+2/z=1
We move all terms to the left:
1/2z+2/z-(1)=0
Domain of the equation: 2z!=0
z!=0/2
z!=0
z∈R
Domain of the equation: z!=0We calculate fractions
z∈R
z/2z^2+4z/2z^2-1=0
We multiply all the terms by the denominator
z+4z-1*2z^2=0
We add all the numbers together, and all the variables
5z-1*2z^2=0
Wy multiply elements
-2z^2+5z=0
a = -2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-2)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-2}=\frac{-10}{-4} =2+1/2 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-2}=\frac{0}{-4} =0 $
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