1/2z+6=3/2(-4)+6)

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Solution for 1/2z+6=3/2(-4)+6) equation:



1/2z+6=3/2(-4)+6)
We move all terms to the left:
1/2z+6-(3/2(-4)+6))=0
Domain of the equation: 2z!=0
z!=0/2
z!=0
z∈R
We add all the numbers together, and all the variables
1/2z-(3/2(-4)+6))+6=0
We calculate fractions
()/(4z^2(-)+(-(3*2z)/(4z^2(-)=0
We calculate terms in parentheses: +()/(4z^2(-)+(-(3*2z)/(4z^2(-), so:
)/(4z^2(-)+(-(3*2z)/(4z^2(-
We can not solve this equation

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