1/2z+6=32(z+6)

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Solution for 1/2z+6=32(z+6) equation: 



1/2z+6=32(z+6)

We move all terms to the left:

1/2z+6-(32(z+6))=0



Domain of the equation: 2z!=0

z!=0/2

z!=0

z∈R



We multiply all the terms by the denominator


-((32(z+6)))*2z+6*2z+1=0

Wy multiply elements

-((32(z+6)))*2z+12z+1=0

We add all the numbers together, and all the variables

12z-((32(z+6)))*2z+1=0

We move all terms containing z to the left, all other terms to the right

12z-((32(z+6)))*2z=-1

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