1/2z-2/7z=1/5(3z-1)

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Solution for 1/2z-2/7z=1/5(3z-1) equation: 


z in (-oo:+oo)

(1/2)*z-((2/7)*z) = (1/5)*(3*z-1) // - (1/5)*(3*z-1)

(1/2)*z-((1/5)*(3*z-1))-((2/7)*z) = 0

(-1/5)*(3*z-1)+(1/2)*z+(-2/7)*z = 0

z/2-1/5*(3*z-1)+(-2*z)/7 = 0

(-1/5*2*7*(3*z-1))/(2*7)+(7*z)/(2*7)+(-2*2*z)/(2*7) = 0

7*z-1/5*2*7*(3*z-1)-2*2*z = 0

14/5-7/5*z-4*z = 0

14/5-27/5*z = 0

(14/5-27/5*z)/(2*7) = 0

(14/5-27/5*z)/(2*7) = 0 // * 2*7

14/5-27/5*z = 0

14/5-27/5*z = 0 // - 14/5

-27/5*z = -14/5 // : -27/5

z = -14/5/(-27/5)

z = 14/27

z = 14/27

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