1/3((2x-8+1))=19

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Solution for 1/3((2x-8+1))=19 equation:



1/3((2x-8+1))=19
We move all terms to the left:
1/3((2x-8+1))-(19)=0
Domain of the equation: 3((2x-8+1))!=0
x∈R
We add all the numbers together, and all the variables
1/3((2x-7))-19=0
We multiply all the terms by the denominator
-19*3((2x-7))+1=0
Wy multiply elements
-57x((+1=0

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