1/3(-12)+y=12

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Solution for 1/3(-12)+y=12 equation: 



1/3(-12)+y=12

We move all terms to the left:

1/3(-12)+y-(12)=0

determiningTheFunctionDomain
y-12+1/3(-12)=0

We multiply all the terms by the denominator


y*3(-12)+1-12*3(-12)=0

We add all the numbers together, and all the variables

y*3(-12)+433=0

Wy multiply elements

3y^2(-+433=0

We use the square of the difference formula

3y^2(-433=0

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