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1/3(-12k+39)=6+15k
We move all terms to the left:
1/3(-12k+39)-(6+15k)=0
Domain of the equation: 3(-12k+39)!=0We add all the numbers together, and all the variables
k∈R
1/3(-12k+39)-(15k+6)=0
We get rid of parentheses
1/3(-12k+39)-15k-6=0
We multiply all the terms by the denominator
-15k*3(-12k+39)-6*3(-12k+39)+1=0
Wy multiply elements
-45k^2(--18k(-+1=0
We use the square of the difference formula
-45k^2(+18k(-1=0
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