1/3(-27j+18)=-9j+6

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Solution for 1/3(-27j+18)=-9j+6 equation: 



1/3(-27j+18)=-9j+6

We move all terms to the left:

1/3(-27j+18)-(-9j+6)=0



Domain of the equation: 3(-27j+18)!=0

j∈R



We get rid of parentheses

1/3(-27j+18)+9j-6=0

We multiply all the terms by the denominator


9j*3(-27j+18)-6*3(-27j+18)+1=0

Wy multiply elements

27j^2(--18j(-+1=0

We use the square of the difference formula

27j^2(+18j(-1=0

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