1/3(-9k+33)=2+12k

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Solution for 1/3(-9k+33)=2+12k equation: 



1/3(-9k+33)=2+12k

We move all terms to the left:

1/3(-9k+33)-(2+12k)=0



Domain of the equation: 3(-9k+33)!=0

k∈R



We add all the numbers together, and all the variables

1/3(-9k+33)-(12k+2)=0

We get rid of parentheses

1/3(-9k+33)-12k-2=0

We multiply all the terms by the denominator


-12k*3(-9k+33)-2*3(-9k+33)+1=0

Wy multiply elements

-36k^2(--6k(-+1=0

We use the square of the difference formula

-36k^2(+6k(-1=0

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