1/3(-9x+12)=19

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Solution for 1/3(-9x+12)=19 equation: 



1/3(-9x+12)=19

We move all terms to the left:

1/3(-9x+12)-(19)=0



Domain of the equation: 3(-9x+12)!=0

x∈R



We multiply all the terms by the denominator


-19*3(-9x+12)+1=0

Wy multiply elements

-57x(-+1=0

We use the square of the difference formula

-57x(-1=0

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