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1/3(-9x+3)=-(-1+3x)
We move all terms to the left:
1/3(-9x+3)-(-(-1+3x))=0
Domain of the equation: 3(-9x+3)!=0We add all the numbers together, and all the variables
x∈R
1/3(-9x+3)-(-(3x-1))=0
We multiply all the terms by the denominator
-((-(3x-1)))*3(-9x+3)+1=0
We calculate terms in parentheses: -((-(3x-1)))*3(-9x+3), so:We add all the numbers together, and all the variables
(-(3x-1)))*3(-9x+3
We add all the numbers together, and all the variables
-9x+(-(3x-1)))*3(+3
Back to the equation:
-(-9x+(-(3x-1)))*3(+3)
-(-9x+(-(3x-1)))*33+1=0
We move all terms containing x to the left, all other terms to the right
-(-9x+(-(3x-1)))*33=-1
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