1/3(1-3x)+3=2(2-x)

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Solution for 1/3(1-3x)+3=2(2-x) equation: 



1/3(1-3x)+3=2(2-x)

We move all terms to the left:

1/3(1-3x)+3-(2(2-x))=0



Domain of the equation: 3(1-3x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-3x+1)-(2(-1x+2))+3=0

We multiply all the terms by the denominator


-((2(-1x+2)))*3(-3x+1)+3*3(-3x+1)+1=0



We calculate terms in parentheses: -((2(-1x+2)))*3(-3x+1), so:

(2(-1x+2)))*3(-3x+1

We add all the numbers together, and all the variables

-3x+(2(-1x+2)))*3(+1

Back to the equation:

-(-3x+(2(-1x+2)))*3(+1)



We add all the numbers together, and all the variables

-(-3x+(2(-1x+2)))*31+3*3(-3x+1)+1=0

Wy multiply elements

-(-3x+(2(-1x+2)))*31+9x(-+1=0

We use the square of the difference formula

-(-3x+(2(-1x+2)))*31+9x(-1=0

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