1/3(10-2x)=1/3(8-2x)

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Solution for 1/3(10-2x)=1/3(8-2x) equation: 



1/3(10-2x)=1/3(8-2x)

We move all terms to the left:

1/3(10-2x)-(1/3(8-2x))=0



Domain of the equation: 3(10-2x)!=0

x∈R





Domain of the equation: 3(8-2x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-2x+10)-(1/3(-2x+8))=0

We calculate fractions


(3x(-)/(3(-2x+10)*3(-2x+8)))+(-3x0/(3(-2x+10)*3(-2x+8)))=0



We calculate terms in parentheses: +(3x(-)/(3(-2x+10)*3(-2x+8))), so:

3x(-)/(3(-2x+10)*3(-2x+8))

We add all the numbers together, and all the variables

3x0/(3(-2x+10)*3(-2x+8))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-3x0/(3(-2x+10)*3(-2x+8))), so:

-3x0/(3(-2x+10)*3(-2x+8))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

3x-3x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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