1/3(10x-1)=1/5(12x+1)

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Solution for 1/3(10x-1)=1/5(12x+1) equation: 



1/3(10x-1)=1/5(12x+1)

We move all terms to the left:

1/3(10x-1)-(1/5(12x+1))=0



Domain of the equation: 3(10x-1)!=0

x∈R





Domain of the equation: 5(12x+1))!=0

x∈R



We calculate fractions


(5x1/(3(10x-1)*5(12x+1)))+(-3x1/(3(10x-1)*5(12x+1)))=0



We calculate terms in parentheses: +(5x1/(3(10x-1)*5(12x+1))), so:

5x1/(3(10x-1)*5(12x+1))

We multiply all the terms by the denominator


5x1

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-3x1/(3(10x-1)*5(12x+1))), so:

-3x1/(3(10x-1)*5(12x+1))

We multiply all the terms by the denominator


-3x1

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

5x-3x=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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