1/3(12-2x)=-8(6-x)

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Solution for 1/3(12-2x)=-8(6-x) equation: 



1/3(12-2x)=-8(6-x)

We move all terms to the left:

1/3(12-2x)-(-8(6-x))=0



Domain of the equation: 3(12-2x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-2x+12)-(-8(-1x+6))=0

We multiply all the terms by the denominator


-((-8(-1x+6)))*3(-2x+12)+1=0



We calculate terms in parentheses: -((-8(-1x+6)))*3(-2x+12), so:

(-8(-1x+6)))*3(-2x+12

We add all the numbers together, and all the variables

-2x+(-8(-1x+6)))*3(+12

Back to the equation:

-(-2x+(-8(-1x+6)))*3(+12)



We add all the numbers together, and all the variables

-(-2x+(-8(-1x+6)))*312+1=0

We move all terms containing x to the left, all other terms to the right

-(-2x+(-8(-1x+6)))*312=-1

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