1/3(12-n)+n=36

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Solution for 1/3(12-n)+n=36 equation: 



1/3(12-n)+n=36

We move all terms to the left:

1/3(12-n)+n-(36)=0



Domain of the equation: 3(12-n)!=0

n∈R



We add all the numbers together, and all the variables

1/3(-1n+12)+n-36=0

We add all the numbers together, and all the variables

n+1/3(-1n+12)-36=0

We multiply all the terms by the denominator


n*3(-1n+12)-36*3(-1n+12)+1=0

Wy multiply elements

3n^2(--108n(-+1=0

We use the square of the difference formula

3n^2(+108n(-1=0

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