If it's not what You are looking for type in the equation solver your own equation and let us solve it.
p in (-oo:+oo)
(1/3)*(12*p+3)-p+4 = 0
1/3*(12*p+3)-p+4 = 0
1/3*(12*p+3)-p+4 = 0
3*p+1+4 = 0
3*p+5 = 0
3*p+5 = 0
3*p+5 = 0 // - 5
3*p = -5 // : 3
p = -5/3
p = -5/3
| r=3(b+a) | | 3/7x-8=-4/7x-1 | | 3.2-4d=2-3d+3 | | 233-9x-3*(2x/3-1.09) | | 6-x+2x^3-x^3+x^4-8x^5=0 | | 1/5(x+4)=8x-18(1-x)-7 | | 5m^2+12m+5=0 | | (2x+3)-2(4x+8)=17 | | x=8y+1/9y+6 | | x^2+7x+4= | | n9/n5 | | 7z-3z=-9z-5-5z | | x^-1/3=4 | | 3x-10=37 | | a^2+20a+68=0 | | 4(x-2)-3x=2(x-6) | | 3-4x=1234 | | 3x^2=-12x-6 | | 4x/5=-4 | | u=u-4 | | X-0.14x= | | 3=9x-3 | | a^2-14a+33=0 | | 9x-.025=3x | | 12(x+7)=4(21+3x) | | 3x^2=12x-6 | | 4/3+6/3=10/(y-9) | | 7y=9+5 | | x+(2x-3)=3 | | 5+4t=2t/8 | | -9-5r^2=-94 | | 4/(x+3)-6/(x-3)=10/(x^2-9) |