1/3(12p-15)+27/3=2/5(10-5p)+6

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Solution for 1/3(12p-15)+27/3=2/5(10-5p)+6 equation: 



1/3(12p-15)+27/3=2/5(10-5p)+6

We move all terms to the left:

1/3(12p-15)+27/3-(2/5(10-5p)+6)=0



Domain of the equation: 3(12p-15)!=0

p∈R





Domain of the equation: 5(10-5p)+6)!=0

p∈R



We add all the numbers together, and all the variables

1/3(12p-15)-(2/5(-5p+10)+6)+27/3=0

We add all the numbers together, and all the variables

1/3(12p-15)-(2/5(-5p+10)+6)+9=0

We calculate fractions


(5p(-)/(3(12p-15)*5(-5p+10))+(-6p1/(3(12p-15)*5(-5p+10))+9=0

We can not solve this equation

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