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1/3(12x+2)=4x+1-1/3
We move all terms to the left:
1/3(12x+2)-(4x+1-1/3)=0
Domain of the equation: 3(12x+2)!=0We add all the numbers together, and all the variables
x∈R
1/3(12x+2)-(4x-1/3+1)=0
We get rid of parentheses
1/3(12x+2)-4x-1+1/3=0
We calculate fractions
-4x-1=0
We move all terms containing x to the left, all other terms to the right
-4x=1
x=1/-4
x=-1/4
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