1/3(12x+24)=-1/4(36x-28)

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Solution for 1/3(12x+24)=-1/4(36x-28) equation:



1/3(12x+24)=-1/4(36x-28)
We move all terms to the left:
1/3(12x+24)-(-1/4(36x-28))=0
Domain of the equation: 3(12x+24)!=0
x∈R
Domain of the equation: 4(36x-28))!=0
x∈R
We calculate fractions
(4x3/(3(12x+24)*4(36x-28)))+(-(-3x1)/(3(12x+24)*4(36x-28)))=0
We calculate terms in parentheses: +(4x3/(3(12x+24)*4(36x-28))), so:
4x3/(3(12x+24)*4(36x-28))
We multiply all the terms by the denominator
4x3
We add all the numbers together, and all the variables
4x^3
We do not support expression: x^3

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