1/3(12x-6)-2x+28=-12x-36+6

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Solution for 1/3(12x-6)-2x+28=-12x-36+6 equation: 



1/3(12x-6)-2x+28=-12x-36+6

We move all terms to the left:

1/3(12x-6)-2x+28-(-12x-36+6)=0



Domain of the equation: 3(12x-6)!=0

x∈R



We add all the numbers together, and all the variables

1/3(12x-6)-2x-(-12x-30)+28=0

We add all the numbers together, and all the variables

-2x+1/3(12x-6)-(-12x-30)+28=0

We get rid of parentheses

-2x+1/3(12x-6)+12x+30+28=0

We multiply all the terms by the denominator


-2x*3(12x-6)+12x*3(12x-6)+30*3(12x-6)+28*3(12x-6)+1=0

Wy multiply elements

-6x^2(1+36x^2(1+90x(1+84x(1+1=0

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