1/3(12x-6)=-2x+16

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Solution for 1/3(12x-6)=-2x+16 equation:



1/3(12x-6)=-2x+16
We move all terms to the left:
1/3(12x-6)-(-2x+16)=0
Domain of the equation: 3(12x-6)!=0
x∈R
We get rid of parentheses
1/3(12x-6)+2x-16=0
We multiply all the terms by the denominator
2x*3(12x-6)-16*3(12x-6)+1=0
Wy multiply elements
6x^2(1-48x(1+1=0

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