1/3(12x-6)=-6+8x

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Solution for 1/3(12x-6)=-6+8x equation: 



1/3(12x-6)=-6+8x

We move all terms to the left:

1/3(12x-6)-(-6+8x)=0



Domain of the equation: 3(12x-6)!=0

x∈R



We add all the numbers together, and all the variables

1/3(12x-6)-(8x-6)=0

We get rid of parentheses

1/3(12x-6)-8x+6=0

We multiply all the terms by the denominator


-8x*3(12x-6)+6*3(12x-6)+1=0

Wy multiply elements

-24x^2(1+18x(1+1=0

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