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(1/3)*(15*x+27) = 5*x+9 // - 5*x+9
(1/3)*(15*x+27)-(5*x)-9 = 0
(1/3)*(15*x+27)-5*x-9 = 0
1/3*(15*x+27)-5*x-9 = 0
1/3*(15*x+27)-5*x-9 = 0
9-9 = 0
0 = 0
0 = 0
x belongs to the empty set
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