1/3(15x-21)=1/4(20-32x)

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Solution for 1/3(15x-21)=1/4(20-32x) equation: 



1/3(15x-21)=1/4(20-32x)

We move all terms to the left:

1/3(15x-21)-(1/4(20-32x))=0



Domain of the equation: 3(15x-21)!=0

x∈R





Domain of the equation: 4(20-32x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(15x-21)-(1/4(-32x+20))=0

We calculate fractions


(4x(-)/(3(15x-21)*4(-32x+20)))+(-3x1/(3(15x-21)*4(-32x+20)))=0



We calculate terms in parentheses: +(4x(-)/(3(15x-21)*4(-32x+20))), so:

4x(-)/(3(15x-21)*4(-32x+20))

We add all the numbers together, and all the variables

4x0/(3(15x-21)*4(-32x+20))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-3x1/(3(15x-21)*4(-32x+20))), so:

-3x1/(3(15x-21)*4(-32x+20))

We multiply all the terms by the denominator


-3x1

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

4x-3x=0

We add all the numbers together, and all the variables

x=0

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