1/3(18+12q)=6(2q-7

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Solution for 1/3(18+12q)=6(2q-7 equation: 



1/3(18+12q)=6(2q-7

We move all terms to the left:

1/3(18+12q)-(6(2q-7)=0



Domain of the equation: 3(18+12q)!=0

q∈R



We add all the numbers together, and all the variables

1/3(12q+18)-(6(2q-7)=0

We multiply all the terms by the denominator


-((6(2q-7))*3(12q+18)+1=0

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