1/3(18-12q)=6(2q-7)

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Solution for 1/3(18-12q)=6(2q-7) equation: 



1/3(18-12q)=6(2q-7)

We move all terms to the left:

1/3(18-12q)-(6(2q-7))=0



Domain of the equation: 3(18-12q)!=0

q∈R



We add all the numbers together, and all the variables

1/3(-12q+18)-(6(2q-7))=0

We multiply all the terms by the denominator


-((6(2q-7)))*3(-12q+18)+1=0



We calculate terms in parentheses: -((6(2q-7)))*3(-12q+18), so:

(6(2q-7)))*3(-12q+18

We add all the numbers together, and all the variables

-12q+(6(2q-7)))*3(+18

Back to the equation:

-(-12q+(6(2q-7)))*3(+18)



We add all the numbers together, and all the variables

-(-12q+(6(2q-7)))*318+1=0

We move all terms containing q to the left, all other terms to the right

-(-12q+(6(2q-7)))*318=-1

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