1/3(18-6x)=1/2(16-4x)

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Solution for 1/3(18-6x)=1/2(16-4x) equation: 



1/3(18-6x)=1/2(16-4x)

We move all terms to the left:

1/3(18-6x)-(1/2(16-4x))=0



Domain of the equation: 3(18-6x)!=0

x∈R





Domain of the equation: 2(16-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(-6x+18)-(1/2(-4x+16))=0

We calculate fractions


(2x(-)/(3(-6x+18)*2(-4x+16)))+(-3x0/(3(-6x+18)*2(-4x+16)))=0



We calculate terms in parentheses: +(2x(-)/(3(-6x+18)*2(-4x+16))), so:

2x(-)/(3(-6x+18)*2(-4x+16))

We add all the numbers together, and all the variables

2x0/(3(-6x+18)*2(-4x+16))

We multiply all the terms by the denominator


2x0

We add all the numbers together, and all the variables

2x

Back to the equation:

+(2x)





We calculate terms in parentheses: +(-3x0/(3(-6x+18)*2(-4x+16))), so:

-3x0/(3(-6x+18)*2(-4x+16))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

2x-3x=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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