1/3(18u-3u+21)=5+4u

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Solution for 1/3(18u-3u+21)=5+4u equation: 



1/3(18u-3u+21)=5+4u

We move all terms to the left:

1/3(18u-3u+21)-(5+4u)=0



Domain of the equation: 3(18u-3u+21)!=0

u∈R



We add all the numbers together, and all the variables

1/3(15u+21)-(4u+5)=0

We get rid of parentheses

1/3(15u+21)-4u-5=0

We multiply all the terms by the denominator


-4u*3(15u+21)-5*3(15u+21)+1=0

Wy multiply elements

-12u^2(1-15u(1+1=0

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